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PES 112 Spring
2003
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General Physics
II
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Solutions to the problem sets will be available on the day
following the day they are due. They will be on Reserve at the
Library and also available in the Science Learning Center (Science
145).
Solutions to some problems in the book can be found on the web at
the text
book web site.
Answers to odd numbered problems are in the back of the
book. If your answer differs slightly it is probably because you
rounded off by plugging numbers into the problem early. The best
method is to keep everything as algebraic symbols until the very end
of the problem and then plug in the values. This will help to
eliminate rounding errors. I will post the answers to the even
numbered problems after the problem set has been turned in.
Be sure and SHOW YOUR WORK on all assigned problems.
Problem Sets:
Problem Set 1: Due Wednesday, January 29,
2003
Chapter 23
- Problem # 2 - GRADED
- answers: a: Fel = 1.59x10-9 N, b:
Fgrav= 1.29x10-45N so electric force is
1.24x1036 times larger, c: q/m =
8.61x10-11 to have the forces equal.
- Problem # 8
- answers: x = 0.634d from left end. Stable equilibrium if
third bead has positive charge.
- Problem # 16
- answers: a: E = -599 N/C i - 2700 N/c
j , b: F = -3.00 i - 13.5 j
µN
- Problem # 25 - GRADED
- Problem # 42
- answers: a = -5.76x1013 i
m/s2, b: v = 2.84x106 i
m/s, c: t = 4.93x10-8 s
- Problem # 55 - GRADED
Common problems on this problem
set:
- carelessness
- not showing work
- mC
= microCoulombs = 10-6 Coulombs
- nC = nanoCoulombs = 10-9
Coulombs
- qq = q2 not 2q
- confusion on definitions of sine and
cosine
- average = 6.05 / 9
Problem Set 2: Due Wednesday, February 5,
2003
Chapter 24
- Problem # 5 - GRADED
- Problem # 16
- part b is intended to be quite simple - the charge is still
surrounded by a sphere but you are only looking at the flux
through half of that sphere.
- be sure and answer in words the question about radius
too!
- answers: a: flux = 1.36x106 Nm2/C ,
b: flux = 6.78x105 Nm2/C , c: No
- Problem # 21 - GRADED
- Problem # 27 - GRADED
- Problem # 38
- answers: use Gauss's Law to find charge density =
1.15x10-9 C/m2
- Problem # 41
- Problem # 56
- answers: a: Q = -4.00 nC, b: Q' = 9.56 nC, c: Q1
= 4.00 nC Q2=5.56 nC
Common problems on this problem
set:
- trouble identifying angles
correctly for dot products
- missing units on answers
- area of a cylindrical surface (not
counting the ends) - 2(pi)rL (not pi r2L- which has the
wrong units)
- 1/0 = infinity !!!!! so does
1/02
- SHOW YOUR WORK (especially on odd
problems where the answers are in the back of the
book)
- Problems that ask about flux are MUCH
easier that problems that ask for E. Often you can use
Gauss's Law and skip right over the E and A and just consider the
charge enclosed.
- average = 7.21 / 9
If you want more practice, take a look at problems 15, 29, 47, 55,
and 59. The solutions to all of these problems are on the web at the
text
book web site.
Problem Set 3: Due Wednesday,
February 12, 2003
Chapter 25 (problems from sections 1-5)
Notice the Note in the book that says to assume a reference
level of potential of V=0 at r=infinity unless told otherwise in
the problem.
- Problem # 9
- Problem # 16 - GRADED
- answers: a) V1= 1.44x10-7 V, b) DELTA
V = -7.19x10-8V, c) V at 1 cm =
-1.44x10-7V, V at 2cm = 7.19x108 V
- Problem # 17
- Problem # 22 - GRADED
- Problem # 33
- Problem # 38 - GRADED
- answers: a) for r<R E=0, b) for r>R E =
kQ/r2
- Problem # 42
Common problems on this problem
set:
- read the problem carefully: potential
energy and potential are different things !
- If asked for a potential
difference:
- do not just calculate one
potential
- do not ADD potentials (difference
=> subtraction)
- The total potential energy required to
assemble a collection of charges from infinity (equation 25.14) is
quite different from the potential energy of interaction of one
test charge interacting with an existing collection of charges
(equation 25.12 multiplied by the test charge).
- problems taking derivatives of constants
and powers of r
- average = 7.5 / 9
If you want more practice, take a look at problems 9, 23,
37, and 49. The solutions to all of these problems are on the web at
the text
book web site.
Problem Set 4: Due Wednesday,
February 26, 2003
Chapter 26 (problems from sections 1-5)
- Problem # 6 - GRADED
- answers: C = 11.1 nF, Q = 26.6C (many
people just calculated Q directly without C and I gave full
credit)
- Problem # 17 - GRADED
- Problem # 18
- a) C = 3.53 micro F, b) V1 = 6.35 V, V2 = 2.65 V , c) Q1 =
Q2 = 31.8 micro C
- Problem # 29
- if you had trouble on this one, my solutions in the library
and SLC have lots of pictures!
- Problem # 32
- a) U = 0.15 J, b) V = 268 V
- Problem # 45 - GRADED
Common problems on this problem
set:
- unit conversion: 1 km2 =
106 m2 (not 1000)
- read the problem carefully - #6 said to
treat this like a parallel plate capacitor
- read the problem and do each part
!!
- average = 7.61 / 9
If you want more practice, take a look at problems 7, 11, 21, 35
and 57. The solutions to all of these problems are on the web at the
text
book web site.
Problem Set 5: Due Wednesday, March
5, 2003
Chapter 27
- Problem # 6- GRADED
- answer: I = q/T = q(omega)/2 pi ..... where omega is the
angular frequency
- Problem # 7
- Problem # 14
- answer: a) R = 3.75 kOhms, b) length = 536 meters
- Problem # 27 - GRADED
- Problem # 30 - GRADED
- answer: Rn = 5.56 kOhms, RC = 4.44
kOhms
- Problem # 43
- Problem # 59
Common problems on this problem
set:
- on Number 6, some people tried to use
the expression for current that involved drift velocity. This
concept is only defined inside a solid and so does not apply
here.
- SHOW YOUR WORK
- On Number 30, many of your solutions
were IDENTICAL to the Solutions Manual. Could you do this problem
if it appears on the Exam? I encourage you to get help and talk to
others - but make sure that YOU know how to do the
problem.
- average = 7.24 / 9
If you want more practice, take a look at problems 3, 15, 25, 39
and 57. The solutions to all of these problems are on the web at the
text
book web site.
Problem Set 6: Due Wednesday, March
12, 2003
Chapter 28
- Problem # 3
- Problem # 11
- Problem # 16
- answer: two resistors are 470 Ohms and 220 Ohms
- Problem # 22
- answers: a) current through R1 = 0.385 mA, current through
R2 = 3.08 mA, current through R3 = 2.69 mA; b) potential
difference from c to f is -69.2V with point c at the higher
potential.
- Problem # 23 - GRADED
- I fiind the solution manual confusing for this problem. My
solutions on reserve in the library and SLC show a much more
straight-forward solution.
- Problem # 34 - GRADED
- answers: a) RC = 12.0 seconds; b) q(t) = 36 micro C (1 -
e-t/12) ... I(t) = 3 microA e-t/12
- Problem # 53 - GRADED
Common problems on this problem
set:
- SHOW YOUR WORK
- Some trouble setting up Kirchhoff's
Rules - although most of you appear to be getting this
OK.
- The maximum charge on a capactor = VC
(or emf x C).
- When doing Kirchhoff's loop rule, the
reason it all adds to zero is that you are back where you started
and there is no potential difference. If you do NOT come back to
where you started, then the 0 is replaced by the potential
difference between where you started and where you
stopped.
- In order for a current to flow, there
must be a complete circuit. If the circuit is broken, no current
will flow. In problem 53 no current will flow in the small wire
with the 4V power supply or in the small wire with the 10 Ohm
resistor.
- average = 5.23 / 9
If you want more practice, take a look at problems 1, 9, 19, 29,
and 47. The solutions to all of these problems are on the web at the
text
book web site.
Problem Set 7: Due Wednesday, April
2, 2003
Chapter 29
- Problem # 4 - GRADED
- answers: a) F = 8.67 x 10-14N, b) a = 5.19 x
1013 m/s2
- Problem # 7 - GRADED
- Problem # 18
- answers: segment ab F = 0, segment bc F = 0.4 N in
-i direction, segment cd F = 0.4 in -k direction,
segment da F= 0.4 in (k + i) direction
- Problem # 27 - GRADED
- Problem # 34
- answer: B = 6.56 x 10-2 Tesla
Common problems on this problem
set:
- SHOW YOUR WORK
- UNITS !!
- trouble converting units
- kg is the MKS unit for mass (not
grams)
- Remember that vectors have a direction
as well as a magnitude
- average = 7.86/9
If you want more practice, take a look at problems 1, 13, 21, 25,
and 47. The solutions to all of these problems are on the web at the
text
book web site.
Problem Set 8: Due Wednesday, April
9, 2003
Chapter 30 (sections 1-4)
- Problem # 2
- answer: B = 2.61 x 10-7 T into the page
- Problem # 7 - don't work too hard
- Problem # 18 - GRADED
- answers: a) currents are in opposite direction, b) I = 67.8
Amps
- Problem # 21
- Problem # 24 - GRADED
- answers: a) B = 1 x 10-5 T, b) r = 2.50 cm
beyond the conductor's surface
- Problem # 31 - need Ohm's Law, find n by inverting the wire
width per turn - GRADED
Common problems on this problem
set:
- SHOW YOUR WORK
- confusion over radius sometimes - when
you see an "r" in an equation what is it the radius or distance
of?
- average = 6.50/9
If you want more practice, take a look at problems 5, 19, 25, 29,
and 55. The solutions to all of these problems are on the web at the
text
book web site.
Problem Set 9: Due Wednesday, April
16, 2003
Chapter 30 (section 8) and Chapter 31
- Chapter 30
- Chapter 31
- Problem # 4
- answers: a) emf = (ABmax / tau)
e-t/tau , b) at t = 2 s emf = 3.79 mV, c) max at
t=0 emf = 28 mV
- Problem #14 - GRADED
- answer: emf = -N(muo)nImax (pi)
R2 (alpha) e-(alpha)t
- Problem # 23
- Problem # 26
- answers: a) current to the right in resistor, b) current
to the right, c) current to the right d) B into the
paper
- Problem # 35 - GRADED
Common problems on this problem
set:
- SHOW YOUR WORK
- some confusion on symbols (N vs n, r vs.
R)
- some problems taking
derivatives
- average = 7.3/9
If you want more practice, take a look at problems 5, 7, 37, 45,
and 73. The solutions to all of these problems are on the web at the
text
book web site.
Problem Set 10: Due Wednesday, April
30, 2003
Chapter 32
- Problem # 8 - GRADED
- answer: flux = 1.92 x 10-5 T m2
- Problem # 9 - GRADED
- Problem # 19
- Problem # 34 - GRADED
- answers: a) U = 27.8 J, b) t = 1.85 x 10-2
s
- Problem # 44
- Problem # 49
Common problems on this problem
set:
- SHOW YOUR WORK
- missing signs in places where it matters
(like dI/dt on 32.9)
- average = 8.3/9
If you want more practice, take a look at problems 7, 21, 29, 35,
and 55. The solutions to all of these problems are on the web at the
text
book web site.
Problem Set 11: Due FRIDAY, May 9,
2003
Chapter 33
- Problem # 7
- Problem # 12 - GRADED
- answer: (Imax = 22.5 A, I(t) = 19.5 A) U = 3.80
J
- Problem # 25
- Problem # 30
- answer:(XL - XC) = 60.0 Ohms, PHI =
53.1 degrees, Irms = 2.80 A, P = 353 W.
Chapter 34
- Problem # 4 - GRADED
- Problem # 13 - GRADED
- Problem # 23
Common problems on this problem
set:
- some trouble with the phase angle on
33.12. When you are told that the current is zero at t=0, that is
telling you the phase angle.
- average = 8.07/9
If you want more practice, take a look at Chapter 33 problems 11,
23, 29, and 55 and Chapter 34 problems 5, 15, 17. and 29. The
solutions to all of these problems are on the web at the text
book web site.
Send comments about these pages to: tchriste@uccs.edu